3m^2-m-1=0

Solution for 3m^2-m-1=0 equation:

3m^2-m-1=0

We add all the numbers together, and all the variables

3m^2-1m-1=0

a = 3; b = -1; c = -1;
Δ = b2-4ac
Δ = -12-4·3·(-1)
Δ = 13
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{13}}{2*3}=\frac{1-\sqrt{13}}{6}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{13}}{2*3}=\frac{1+\sqrt{13}}{6}
$